{"id":17625,"date":"2024-03-16T13:35:54","date_gmt":"2024-03-16T13:35:54","guid":{"rendered":"https:\/\/soicau5027.minhngocxoso.com\/lo-khung-la-gi-cach-nuoi-lo-khung-2-ngay-hieu-qua\/"},"modified":"2024-03-16T13:35:54","modified_gmt":"2024-03-16T13:35:54","slug":"lo-khung-la-gi-cach-nuoi-lo-khung-2-ngay-hieu-qua","status":"publish","type":"post","link":"https:\/\/soicauxs86.com\/lo-khung-la-gi-cach-nuoi-lo-khung-2-ngay-hieu-qua\/","title":{"rendered":"l\u00f4 khung l\u00e0 g\u00ec? c\u00e1ch nu\u00f4i l\u00f4 khung 2 ng\u00e0y hi\u1ec7u qu\u1ea3"},"content":{"rendered":"
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L\u00f4 khung l\u00e0 g\u00ec? Ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i l\u00f4 khung nh\u01b0 th\u1ebf n\u00e0o \u0111\u1ec3 ch\u1ecdn ra nh\u1eefng c\u1eb7p s\u1ed1 \u0111\u1eb9p nh\u1ea5t \u0111\u00e1nh trong khung 2 ng\u00e0y \u0111\u1ea1t hi\u1ec7u qu\u1ea3. D\u01b0\u1edbi \u0111\u00e2y s\u1ebd t\u1ed5ng h\u1ee3p v\u00e0 chia s\u1ebb ph\u01b0\u01a1ng ph\u00e1p t\u00ednh l\u00f4 khung v\u00e0 c\u00e1ch nu\u00f4i l\u00f4 khung 2 ng\u00e0y hi\u1ec7u qu\u1ea3 an to\u00e0n, c\u00f3 l\u00e3i. Tuy nhi\u00ean, ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u1ec9 th\u00edch h\u1ee3p v\u1edbi nh\u1eefng ng\u01b0\u1eddi c\u00f3 v\u1ed1n th\u1ea5p v\u00e0 ch\u1ec9 ch\u01a1i v\u00e0i \u0111i\u1ec3m \u0111\u1ebfn v\u00e0i ch\u1ee5c \u0111i\u1ec3m m\u1ed7i ng\u00e0y.<\/p>\n

Ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i l\u00f4 khung 2 ng\u00e0y<\/span><\/h2>\n

Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ph\u00f9 h\u1ee3p v\u1edbi nh\u1eefng ng\u01b0\u1eddi ch\u01a1i c\u00f3 s\u1ed1 ti\u1ec1n \u00edt kho\u1ea3ng d\u01b0\u1edbi 1 tri\u1ec7u v\u00e0 ph\u00f9 h\u1ee3p v\u1edbi v\u1edbi nh\u1eefng ng\u01b0\u1eddi kh\u00f4ng \u0111\u00e1nh l\u1edbn. V\u00ec v\u1eady, khi theo ph\u01b0\u01a1ng ph\u00e1p n\u00e0y b\u1ea1n c\u00f3 th\u1ec3 g\u1ea5p ti\u1ec1n theo t\u1ef7 l\u1ec7 1\/3.<\/p>\n

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V\u00ed d\u1ee5: Ng\u00e0y th\u1ee9 nh\u1ea5t b\u1ea1n ch\u01a1i 5 \u0111i\u1ec3m 1 con. Nh\u01b0ng n\u1ebfu ng\u00e0y th\u1ee9 nh\u1ea5t c\u1eb7p s\u1ed1 ch\u01b0a v\u1ec1 th\u00ec sang ng\u00e0y th\u1ee9 2 b\u1ea1n ch\u01a1i th\u00eam 15 \u0111i\u1ec3m\/ con. N\u1ebfu h\u1ebft khung 2 ng\u00e0y kh\u00f4ng ra th\u00ec k\u1ebft th\u00fac 2 ng\u00e0y \u0111\u00f3 b\u1ea1n v\u00e0o khung m\u1edbi nh\u01b0ng ph\u1ea3i b\u1eaft \u0111\u1ea7u ch\u01a1i \u1edf m\u1ee9c ng\u00e0y th\u1ee9 1 l\u00e0 5 \u0111i\u1ec3m \/ con.<\/p>\n

H\u01b0\u1edbng d\u1eabn c\u00e1ch ch\u01a1i l\u00f4 khung 2 ng\u00e0y chu\u1ea9n<\/span><\/h2>\n

\u0110\u1ec3 ch\u01a1i \u0111\u01b0\u1ee3c ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i l\u00f4 khung 2 ng\u00e0y b\u1ea1n c\u1ea7n d\u1ef1a v\u00e0o b\u1ea3ng k\u1ebft qu\u1ea3 s\u1ed1 x\u1ed1 mi\u1ec1n B\u1eafc v\u00e0 theo ph\u01b0\u01a1ng ph\u00e1p sau:<\/p>\n

\u2013<\/em> Ng\u00e0y ch\u1ee7 nh\u1eadt:<\/em> L\u1ea5y con th\u1ee9 1 v\u00e0 th\u1ee9 3 c\u1ee7a gi\u1ea3i 3.6 l\u00e0m c\u1ea7u. V\u00ed d\u1ee5: Gi\u1ea3i 3.6 ng\u00e0y th\u1ee9 7 v\u1ec1 67819. V\u1eady ch\u1ee7 nh\u1eadt ta \u0111\u00e1nh 68.<\/p>\n

Ng\u00e0y th\u1ee9 2: N\u1ebfu b\u1ea1n ch\u01a1i b\u1eaft \u0111\u1ea7u v\u00e0o ng\u00e0y th\u1ee9 2 th\u00ec n\u00ean xem l\u1ea1i b\u1ea3ng k\u1ebft qu\u1ea3 ng\u00e0y ch\u1ee7 nh\u1eadt. Soi l\u1ea1i gi\u1ea3i 5 v\u00e0 gi\u1ea3i 6, gh\u00e9p con \u0111\u1ea7u ti\u00ean c\u1ee7a gi\u1ea3i 5.6 v\u00e0 6.1 \u0111\u1ec3 \u0111\u01b0\u1ee3c c\u00e1c c\u1eb7p s\u1ed1 v\u00e0 \u0111\u00e1nh.<\/p>\n

Ng\u00e0y th\u1ee9 3: C\u1ed9ng 2  s\u1ed1 c\u1ee7a gi\u1ea3i 7.3 \u0111\u1ec3 \u0111\u00e1nh. V\u00ed d\u1ee5, gi\u1ea3i 7.3 c\u1ee7a ng\u00e0y th\u1ee9 2 l\u00e0 70, b\u1ea1n l\u1ea5y 7+0= 07, \u0111\u00e1nh l\u00f4 07. Ch\u1ecdn con th\u1ee9 2 c\u1ee7a gi\u1ea3i 4.3 v\u00e0 4.4. V\u00ed d\u1ee5, gi\u1ea3i 4.3 v\u00e0 4.4 ng\u00e0y th\u1ee9 hai l\u00e0 5543, 7574. V\u1eady ng\u00e0y th\u1ee9 3 b\u1ea1n \u0111\u00e1nh l\u00f4 55.<\/p>\n

Ng\u00e0y th\u1ee9 4: C\u1ed9ng d\u1ed3n t\u1ea5t c\u1ea3 gi\u1ea3i 7, v\u00ed d\u1ee5: Gi\u1ea3i 7 ng\u00e0y th\u1ee9 ba ra l\u00e0: 51-92-70-90. B\u1ea1n c\u1ed9ng d\u1ed3n 51 + 92 + 70 + 90 = 203, v\u1eady \u0111\u00e1nh 03.<\/p>\n

\u2013<\/em>Ng\u00e0y th\u1ee9 5: Gh\u00e9p c\u1ea7u con th\u1ee9 2 v\u00e0 th\u1ee9 3 c\u1ee7a gi\u1ea3i 5.2. V\u00ed d\u1ee5: K\u1ebft qu\u1ea3 gi\u1ea3i 5.2 c\u1ee7a ng\u00e0y th\u1ee9 4 l\u00e0 5849. V\u1eady ng\u00e0y th\u1ee9 5 b\u1ea1n \u0111\u00e1nh 84.<\/p>\n

Ng\u00e0y th\u1ee9 6: Gh\u00e9p 2 con \u0111\u1ea7u gi\u1ea3i 5.4 v\u00e0 5.5. V\u00ed d\u1ee5: G\u1ea3i 5.4, 5.5 c\u1ee7a ng\u00e0y th\u1ee9 5 ra l\u00e0 5028 v\u00e0 5522. V\u1eady th\u1ee9 6 b\u1ea1n \u0111\u00e1nh 55.<\/p>\n

Ng\u00e0y th\u1ee9 7:  C\u1ed9ng d\u1ed3n gi\u1ea3i 5.5 l\u1ea1i, v\u00ed d\u1ee5: Gi\u1ea3i 5.5 h\u00f4m th\u1ee9 6 ra l\u00e0 5522. B\u1ea1n c\u1ed9ng l\u1ea1i h\u1ebft: 5 + 5 + 2 + 2 = 14. \u0110\u1ebfn th\u1ee9 7 th\u00ec \u0111\u00e1nh con 14.<\/p>\n

C\u00e1ch soi c\u1ea7u nu\u00f4i khung 3 ng\u00e0y <\/strong><\/span><\/h2>\n

\u1ede \u0111\u00e2y ch\u00fang t\u00f4i s\u1ebd d\u1ef1a theo xsmb 100 ng\u00e0y tr\u01b0\u1edbc \u0111\u1ec3 \u0111\u01b0a ra v\u00ed d\u1ee5 kh\u00f4ng ph\u1ea3i ai c\u0169ng bi\u1ebft cho c\u00e1c b\u1ea1n. C\u00e1ch n\u00e0y c\u0169ng c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng cho c\u00e1c mi\u1ec1n kh\u00e1c nh\u01b0ng mi\u1ec1n b\u1eafc l\u00e0 d\u1ec5 n\u1ed5 nh\u1ea5t.<\/p>\n

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\u0110\u1ec3 ch\u01a1i theo c\u00e1ch n\u00e0y. \u0111\u1ea7u ti\u00ean b\u1ea1n c\u1ea7n ph\u1ea3i c\u00f3 m\u1ed9t c\u1eb7p l\u00f4. C\u1eb7p l\u00f4 n\u00e0y b\u1ea1n c\u00f3 th\u1ec3 t\u00f9y ch\u1ecdn d\u1ef1a v\u00e0o m\u1ed9t trong nh\u1eefng c\u00e1ch ch\u1ecdn b\u1ea1ch th\u1ee7 m\u00e0 ch\u00fang t\u00f4i \u0111\u00e3 h\u01b0\u1edbng d\u1eabn trong nh\u1eefng b\u00e0i tr\u01b0\u1edbc (gi\u1ea3i \u0111\u1eb7c bi\u1ec7t, con \u0111\u1ea7u v\u00e0 cu\u1ed1i gi\u1ea3i 7, l\u00f4 gan c\u1ef1c \u0111\u1ea1i mi\u1ec1n b\u1eafc, c\u1eb7p l\u00f4 gan nh\u1ea5t,\u2026)<\/p>\n

V\u1edbi c\u00e1ch ch\u01a1i n\u00e0y, ph\u00e2n v\u1ed1n h\u1ee3p l\u00fd nh\u1ea5t l\u00e0 1 : 3 : 6 trong 3 ng\u00e0y li\u00ean ti\u1ebfp.<\/p>\n

V\u00ed d\u1ee5 cho d\u1ec5 hi\u1ec3u :<\/strong> B\u1ea1n mu\u1ed1n \u0111\u00e1nh c\u1eb7p 97-79<\/h5>\n

Ng\u00e0y 1 :<\/strong> \u0111\u00e1nh 1\/10 s\u1ed1 ti\u1ec1n cho 97 \u2013 79 (khuy\u1ebfn kh\u00edch \u0111\u00e1nh 2 con 10 \u0111i\u1ec3m)<\/p>\n

Ng\u00e0y 2 :<\/strong> \u0111\u00e1nh 3\/10 s\u1ed1 ti\u1ec1n cho 97- 79 (Ch\u1ec9 \u0111\u00e1nh trong tr\u01b0\u1eddng h\u1ee3p c\u1ea3 2 con \u0111\u1ec1u ch\u01b0a ra \u1edf ng\u00e0y 1). N\u1ebfu ng\u00e0y 1 ra 1 trong 2 con, ta ph\u00e2n b\u1ed5 v\u1ed1n cho con ch\u01b0a n\u1ed5 nhi\u1ec1u h\u01a1n m\u1ed9t ch\u00fat.<\/p>\n

Ng\u00e0y 3 :<\/strong> N\u1ebfu ng\u00e0y 2 v\u1eabn c\u00f2n ch\u01b0a ra, ch\u00fang ta c\u00f3 th\u1ec3 d\u1ed3n h\u1ebft 6 ph\u1ea7n v\u1ed1n c\u00f2n l\u1ea1i cho ng\u00e0y 3 n\u00e0y.\u0110\u00e2y \u0111\u01b0\u1ee3c m\u1ec7nh danh l\u00e0 c\u00e1ch nu\u00f4i l\u00f4 \u0111\u1ec1 hi\u1ec7u qu\u1ea3 nh\u1ea5t. Tuy nhi\u00ean, v\u1eabn c\u1ea7n thi\u1ebft l\u01b0u \u00fd m\u1ed9t v\u00e0i \u0111i\u1ec1u sau<\/p>\n